example usage of vedic / fast maths.

lets see in what all ways the vedic maths or better say fast maths can be used to beat your own mental skills and in some cases, even calculator ;)

Example 1 : Finding Square of a number ending with 5
To find the square of 75

Do the following

Multiply 5 by 5 and put (5X5)=25 as your right part of answer.
=> xxxxxxx25
now,Multiply 7 with the next higher digit
=> 7 X (7+1)=7X8
gives 56 as the left part of the answer
so, Answer is 5625


Example 2 : Calculate 43 X 47 (The above 'rule' works when you multiply 2 numbers with units digits add upto 10 and tenth place same)
3X7=21
xxxxxxx21
4X(4+1)=20

The answer is 2021 Same theory worked here too.

same as above; Find 52 X 58 ? Answer = 3016 How long this take ?

Example 3: Multiply 52 X 11
answer is 572
Write down the number being multiplied
5xxxxxxxxx2
and put the total of the digits between two digits
52 X 11 is [ 5 and 5+2=7 and 2 ] ,
answer is 572
note: in case you want to multiply 52 with 111
just write 7 twice => 5772
in case of 1111
57772

sum,here 5+2 = 7 is written one time lesser than the 1's in the digit.

QUESTION#15

An express train traveled at an average speed of 100 kilometers per hour, stopping for 3 minutes after every 75 kilometers. A local train traveled at an average speed of 50 kilometers, stopping for 1 minute after every 25 kilometers. If the trains began traveling at the same time, how many kilometers did the local train travel in the time it took the express train to travel 600 kilometers?
A)300
B)305
C)307.5
D)1200
E)1236

QUESTION#14

TWO couples and a single person are to be seated on 5 chairs such that no couple is seated next to each other. What is the probability of the above??
A)1/25
B)2/25
C)4/25
D)3/5
E)2/5

QUESTION#13

. Kurt, a painter, has 9 jars of paint:
4 are yellow
2 are red
rest are brown
Kurt will combine 3 jars of paint into a new container to make a new color, which he will name accordingly to the following conditions:
Brun Y if the paint contains 2 jars of brown paint and no yellow
Brun X if the paint contains 3 jars of brown paint
Jaune X if the paint contains at least 2 jars of yellow
Jaune Y if the paint contains exactly 1 jar of yellow
What is the probability that the new color will be Jaune
a) 5/42
b) 37/42
c) 1/21
d) 4/9
e) 5/9

QUESTION#12

If n is an integer from 1 to 96, what is the probability for n*(n+1)*(n+2) being divisible by 8?

A)25%
B)50%
C)62.5%
D)72.5%
E)75%

QUESTION # 11

The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?
A)20
B)25
C)40
D)45
E)50

Answers # 6 to 10

question:6=> AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B)3

(C) 7

(D) 9

(E) Cannot be determined
Ans: AB + CD = AAA

Since AB and CD are two digit numbers, then AAA must be 111

case even if ab and cd are the biggest numbers possible even than 96 + 87 = 183.

Therefore 1B + CD = 111

THATS WHY C=9, FOR ALL VALUES OF B.

PROOF: B can assume any value between 3 and 9

If B = 3, then CD = 111-13 = 98 and C = 9

If B = 9, then CD = 111-19 = 92 and C = 9

So for all B between 3 & 9, C = 9

Therefore the correct answer is D (C = 9)

QUESTION:7

1. A certain quantity of 40% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced?

(A) 1/4

(B) 1/3

(C) 1/2

(D) 2/3

(E) ¾
Ans: Let X be the fraction of solution that is replaced.

Then X*25% + (1-X)*40% = 35%

Solving, you get X = 1/3

QUESTION:8

A bag contains 3 red, 4 black and 2 white balls. What is the probability of drawing a red and a white ball in two successive draws, each ball being put back after it is drawn?

(A) 2/27

(B) 1/9

(C) 1/3

(D) 4/27

(E) 2/9

Ans:

Case I: Red ball first and then white ball P1 = 3/9*2/9= 2/27

Case 2: White ball first and then red ballP2 = 2/9*3/9 = 2/27

Therefore total probability: p1 + p2 = 4/27

QUESTION:9

What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y = 3/4*x - 3?

A) 1.4

B) sqrt(2)

C) 1.7

D) sqrt(3)

E) 2.0

Ans:

The equation of the line will be 3x - 4y - 12 = 0.

This crosses the x and y axis at (0,-3) and (4,0)

The circle has the origin at the center and has a radius of 1 unit.

So it is closest to the given line when, a perpendicular is drawn to the line, which passes through the origin.This distance of the line from the origin is 12 / sqrt (9 + 16) which is 2.4
[Length of perpendicular from origin to line ax +by + c = 0 ismod (c / sqrt (a^2 + b^2))]
The radius is 1 unit.

So the shortest distance is 2.4 - 1 unit = 1.4 units

QUESTION:10

In the square above, 12w = 3x = 4y. What fractional part of the square is shaded?

A) 2/3

B) 14/25

C) 5/9

D) 11/25

E) 3/7

ANSWER:

Since 12w=3x=4y,

w:x=3:12=1:4 and x:y=4:3

so, w = 1x = 4y = 3

the fractional part of the square is shaded:

{(w+x)^2 - [(1/2)wx + (1/2)wx +(1/2)xy + (1/2)w(2w)]}/(w+x)^2

= {(w+x)^2 - [wx + (1/2)xy + w^2)]}/[(w+x)^2]=[(5^2) -(4+6+1)]/(5^2)

= (25 - 11)/25

= 14/25.

Question # 10

In the square above, 12w = 3x = 4y. What fractional part of the square is shaded?

A) 2/3

B) 14/25

C) 5/9

D) 11/25

E) 3/7

INTRODUCTION OF VEDIC MATHEMATICS

• WHAT IS VEDIC MATHEMATICS?

It is an ancient technique, which simplifies multiplication, divisibility,squaring, cubing, square and cube roots.

Even recurring decimals and auxiliary fractions can be handled by Vedic mathematics. Vedic Mathematics forms part of Jyotish Shastra which is one of the six parts of Vedangas. The Jyotish Shastra or Astronomy is made up of three parts called Skandas. A Skanda means the big branch of a tree shooting out of the trunk.

AND THE BEST PART IS - you dont even need a calculator for this purpose.

• What is the basis of Vedic Mathematics?

The basis of Vedic mathematics, are the 16 sutras, which attribute a set of qualities to a
number or a group of numbers. The ancient Hindu scientists (Rishis) of Bharat in 16 Sutras
(Phrases) and 120 words laid down simple steps for solving all mathematical problems in
easy to follow 2 or 3 steps.

Vedic Mental or one or two line methods can be used effectively for solving divisions, reciprocals, factorisation, HCF, squares and square roots, cubes and cube roots, algebraic
equations, multiple simultaneous equations, quadratic equations, cubic equations, biquadratic
equations, higher degree equations, differential calculus, Partial fractions,Integrations, Pythogorus theoram, Apollonius Theoram, Analytical Conics and so on.

Vedic Maths / Vaidic Maths / Vadic Maths (whatever you call)

we are restarting the series we stoped in middile. we posted a lesson about vedic maths for our readers as well but that wasn't carried on properly as well. so now we are starting again from the very begining and this time we will be going from the root of the technique known as
"VEDIC MATHS or VADIC MATHS or VAIDIC MATHS"

WHATEVER YOU CALL IT BUT ITS A BRILLIANT TECHNIQUE THAT CAN MAKE YOU DOUBT YOUR OWN MENTAL CAPABILITIES.

WE SUGGEST ALL READERS TO GO ONE BY ONE AND READ EACH POST VERY SERIOUSLY CAUSE EVERY THING IS RELATED TO EACH OTHER.

Question # 9

What is the least possible distance between a point on the circle x^2 + y^2 = 1 and a point on the line y = 3/4*x - 3?
A) 1.4
B) sqrt (2)
C) 1.7
D) sqrt (3)
E) 2.0

Question # 8 (simple probability)

A bag contains 3 red, 4 black and 2 white balls. What is the probability of drawing a red and a white ball in two successive draws, each ball being put back after it is drawn?
(A) 2/27
(B) 1/9
(C) 1/3
(D) 4/27
(E) 2/9

list of B-schools and programs they offer:

Amity Business School:
8VF-S5-02 MBA – Program

Apex Institute of Management:
JMR-J1-50 MBA - Program

Indian Institute of Foreign Trade:
0CW-RV-46 MBA - Program

Indian Institute of Management Ahmedabad:
CQQ-RR-28 Two-Year Post Graduate Program
CQQ-RR-64 Two-Year Post Graduate Program in Agri-Business Management
CQQ-RR-68 Fellow Program in Management
CQQ-RR-60 One-Year Post Graduate Program for Executives
CQQ-RR-62 One-Year Post Graduate Program for Public Management & Policy

Indian Institute of Management Bangalore:
Q9H-KK-49 Postgraduate Programme
Q9H-KK-32 Postgraduate Program in Software Enterprise Management

Indian Institute of Management Calcutta:
9CP-HT-97 Postgraduate Program in Management
9CP-HT-99 Postgraduate Program for Executives

Indian Institute of Management Lucknow:
J39-VT-91 MBA, Full Time

Indian Institute of Social Welfare and Business Management:
L9Q-BP-77 MBA - Program

Indian School of Business:
N2D-J5-01 MBA, Full Time

Institute of Management Development and Research:
C0F-QJ-23 PgDip in Management

Punjab University:
247-T0-67 MBA - Program

Spicer Memorial College:
1QG-MD-95 MBA - Program

Tata Institute of Social Sciences:
66X-QL-51 MBA - Program

XLRI Jamshedpur:
WW2-8N-93 MBA – Program

Question # 7

A certain quantity of 40% solution is replaced with 25% solution such that the new concentration is 35%.
What is the fraction of the solution that was replaced?
(A) 1/4
(B) 1/3
(C) 1/2
(D) 2/3
(E) 3/4

Question # 6

AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
(A) 1
(B) 3
(C) 7
(D) 9
(E) Cannot be determined

maths formule

we got a wordsheet that consists many useful formule. all formule are common but being together, makes really easy to revise.
first page i am posting right now.


GMAT FORMULAS
Summation Formula = (Number of numbers)/2 * (f + l), where number of numbers = f – l + 1

Percent Change = Difference/Original

Rectangular Solid Volume = L*W*H

Cube Volume = S*S*S

Cylinder Volume = PieRsquaredH

Surface Area (Combined area of all the surfaces, or faces, of a solid)

Surface Area of Rectangular Solid = 2lw + 2lh + 2wh

Surface Area of a Cube = 6ssquared

Principal + Interest = principal * (1+r)>t, where

Total = Group 1 + Group 2 – Both + Neither

Quadratics
• (x + y)2 = x2 + 2xy + y2
• (x – y)2 = x2 – 2xy + y2
• (x + y)(x – y) = x2 – y2

Number of permutations (different arrangements when order matters) = (n!)/(n-r)!

Number of combinations (arrangements when order doesn’t matter) = (n!)/r!(n-r)!

where n = number of objects in the source group
where r = number of objects selected

The length of a given side must be greater than the difference of the other two sides and less tha
the sum of the other two sides.

question #2 correction

guys and gals plz have a look

there is some typing error in question number 2.

actually i typed questions in ms word and pasted them here. which caused this error.

anyways its the correct question

The price of a bushel of corn is currently $3.20, and the price of a peck of wheat is $5.80. The price of corn is increasing at a constant rate of 5x cents per day while the price of wheat is decreasing at a constant rate of {[under root(x)] -x})cents per day. What is the approximate price when a bushel of corn costs the same amount as a peck of wheat?
(A) $4.50(B) $5.10(C) $5.30(D) $5.50(E) $5.60


explain the answer now cause its already answered.