In a basketball contest, players must make 10 free throws. Assuming a player has 90% chance of making each of his shots, how likely is it that he will make all of his first 10 shots?
NOTE: 1. we will announce the name of members who are leading the quiz after posting first 5 questions out of ten.
2. readers can post the answers of anyquestion until i post the answer of those questions.
(answers of first 5 questions will be posted one day after posting the fifth question)
Sunday, November 25, 2007
QUESTION # 4
Posted by Gaurav & Kunal at 11:43 PM
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2 Comments:
The answer is (0.9)^10
Because each throw is an independent event having a 90% probability of success.
Hence (9/10)*(9/10)*(9/10)... 10 times.
kinda incomplete but counted.
:) 1 point for this one dude
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