Tuesday, December 11, 2007

Question # 8 (simple probability)

A bag contains 3 red, 4 black and 2 white balls. What is the probability of drawing a red and a white ball in two successive draws, each ball being put back after it is drawn?
(A) 2/27
(B) 1/9
(C) 1/3
(D) 4/27
(E) 2/9

6 Comments:

SivaG said...

3C1*4C1 / 9C1*9C1 = 4/27
sound right?

Unknown said...

3/9 * 2/9 = 2/27

correct me if am wrong

Gaurav & Kunal said...

noted.

SivaG said...

Right...,
3C1*2C1 / 9C1*9C1 = 2/27

misread the Question

Gaurav & Kunal said...

simple probability that was guys...

Gaurav & Kunal said...

NO ONE GET ANY POINT FOR THIS PARTICULAR QUESTION.
SIVAG YOU CHANGED YOUR ANSWER. :(

CHAT BOX