Question of the day : 25-2-2009
Question type : Problem Solving
A group of four women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?
(A) 7! – 2!3!2!
(B) 7! – 4!3!
(C) 7! – 5!3!
(D) 7 × 2!3!2!
(E) 2!3!2!
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Sunday, March 15, 2009
Question of the day : 25-2-2009
Posted by Gaurav & Kunal at 8:39 PM
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5 Comments:
lets consider 7 seats as unique then 7!... now lets consider three men sitting adjacent as 3! and there are 6!* 3! hence answer a matches with the above said
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