TWO couples and a single person are to be seated on 5 chairs such that no couple is seated next to each other. What is the probability of the above??
A)1/25
B)2/25
C)4/25
D)3/5
E)2/5
Friday, December 28, 2007
QUESTION#14
Posted by Gaurav & Kunal at 10:51 PM
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2 Comments:
The Ans. is (D).
Total no. of possible events are 5C3 * !3 = 60.
The total no. of events (Couple can be together) to be eliminated are 4*!2*3 = 24.
[Couple can be seated together in 4 ways in a row, And they cen be arranged among in !2 ways and the Single person can be seated anywhere in the rermaining 3 Seats]
So no. of events remaining are = 60-24 = 36.
So the probobility is = 36/60 = 3/5.
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